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TX PACT Chemistry (740) Practice Tests & Test Prep by Exam Edge - Topics



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Understanding what is on the TX PACT Chemistry exam is crucial step in preparing for the exam. You will need to have an understanding of the testing domain (topics covered) to be sure you are studying the correct information.

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TX PACT Chemistry Grades 7-12 Exam Blueprint

Understanding the exact breakdown of the TX PACT Chemistry Grades 7-12 test will help you know what to expect and how to most effectively prepare. The TX PACT Chemistry Grades 7-12 has 125 multiple-choice questions The exam will be broken down into the sections below:

TX PACT Chemistry Grades 7-12 Exam Blueprint
Domain Name % Number of
Questions
Nature of Science 18% 23
Matter and Atomic Structure 18% 23
Energy and Chemical Bonding 23% 29
Chemical Reactions 23% 29
Stoichiometry and Solutions 18% 23

TX PACT Chemistry Grades 7-12 - Exam Topics Sample Questions

Which reagent would cause a double replacement reaction to take place in an aqueous solution of Na2SO4 ?

Correct Answer:
ba(no3)2
in the context of the question, you are asked to identify which reagent would cause a double replacement reaction in an aqueous solution of sodium sulfate (na2so4). a double replacement reaction typically involves two compounds in solution exchanging their ions to form two new compounds. for a reaction to be noticeable, one of the products is usually a precipitate, a gas, or a weak electrolyte.

let's consider each option and explain why or why not they would cause a double replacement reaction: **mgi2 (magnesium iodide):** when mgi2 is mixed with na2so4 in an aqueous solution, the potential reaction would be: \[ \text{mgi}_2 + \text{na}_2\text{so}_4 \rightarrow \text{mgso}_4 + 2\text{nai} \] both magnesium sulfate (mgso4) and sodium iodide (nai) are soluble in water. since all products remain in solution as ions and no precipitate or gas is formed, there is no noticeable sign of a reaction in this case. hence, this does not meet the criteria for a double replacement reaction where a precipitate or other non-soluble product must form. **ba(no3)2 (barium nitrate):** when ba(no3)2 is mixed with na2so4, the potential reaction would be: \[ \text{ba(no}_3)_2 + \text{na}_2\text{so}_4 \rightarrow \text{baso}_4 + 2\text{nano}_3 \] barium sulfate (baso4) is known to be insoluble in water and precipitates out of the solution. sodium nitrate (nano3) remains in solution as it is a soluble salt. here, the formation of a precipitate (baso4) clearly indicates a double replacement reaction, making ba(no3)2 the correct answer to the question. **(ch3coo)2ca (calcium acetate):** if (ch3coo)2ca reacts with na2so4, the potential reaction would be: \[ (\text{ch}_3\text{coo})_2\text{ca} + \text{na}_2\text{so}_4 \rightarrow \text{caso}_4 + 2\text{ch}_3\text{coona} \] calcium sulfate (caso4) has a moderate solubility in water, but under some conditions, it might precipitate. acetate ions and sodium ions remain in solution. the formation of a precipitate depends on the concentrations and temperature, so a double replacement reaction might be possible but is not as definitive as with barium nitrate. **k3po4 (potassium phosphate):** for k3po4 reacting with na2so4, the reaction would be: \[ \text{k}_3\text{po}_4 + \text{na}_2\text{so}_4 \rightarrow \text{k}_2\text{so}_4 + \text{na}_3\text{po}_4 \] both potassium sulfate (k2so4) and sodium phosphate (na3po4) are soluble in water. like with mgi2, all products remain dissolved, and no precipitate or gas forms. thus, there is no visible indication of a reaction.

in conclusion, ba(no3)2 is the reagent that would cause a noticeable double replacement reaction in an aqueous solution of na2so4, as it leads to the formation of an insoluble precipitate, barium sulfate (baso4), clearly indicating a chemical change.