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FTCE Chemistry (003) Practice Tests & Test Prep by Exam Edge - Exam Info



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FTCE Chemistry 6-12 - Additional Information

FTCE Chemistry 6-12 - Additional Info Sample Questions

In a chemical reaction, 200g of calcium carbonate is created. Prior to beginning the reaction, the chemist calculates a maximum theoretical mass produced of 350g. What is the percentage yield of the reaction?

Correct Answer:
57%.


the percentage yield of a chemical reaction is an important measure in chemistry, reflecting the efficiency of a reaction. it compares the actual amount of product obtained from a reaction to the amount that was theoretically possible, based on stoichiometry and limiting reactants. calculating the percentage yield helps chemists understand how close they have come to the maximum possible yield and can indicate the presence of side reactions, incomplete reactions, or losses during processing.

to find the percentage yield, you first need two important pieces of data: 1. the actual yield, which is the amount of product actually produced from the reaction. in this case, the actual yield is 200g of calcium carbonate. 2. the theoretical yield, which is the maximum amount of product that could be expected based on the reactants used, assuming the reaction goes to completion under perfect conditions. here, the theoretical yield is 350g.

the formula for calculating percentage yield is: \[ \text{percentage yield} = \left(\frac{\text{actual yield}}{\text{theoretical yield}}\right) \times 100\% \]

applying this formula to the given values: \[ \text{percentage yield} = \left(\frac{200g}{350g}\right) \times 100\% = 57.14\%\]

thus, the percentage yield of the reaction is approximately 57%. this means that 57% of the theoretical maximum amount of calcium carbonate was actually produced. this value helps in evaluating the efficiency of the reaction and in planning adjustments for future experiments to improve yield.